31 - 40 of 49 Questions
# | Question | Ans |
---|---|---|
31. |
In the diagram above, /PQ/ = /PS/ and /QR/ = /SR/. Which of the following is/are true? i. the line PR bisects ∠QRS ii. The line PR is the perpendicular bisector of the line segment QS iii. Every point on PR is equidistant from SP and QP A. I only B. III only C. I and II only D. I and III only E. I, II and III |
E |
32. |
In the diagram, ∠PMN = ∠PRQ and ∠PNM = ∠PQR. If /Pm/ = 3cm, /MQ/ = 7cm and /PN/ = 5cm, find /NR/ A. 1cm B. 3cm C. 31/2 D. 5cm E. 6cm |
A |
33. |
In the diagram above, PQ is a tangent to the circle MTN at T. What is the size of ∠MTN? A. 52o B. 54o C. 66o D. 72o E. 128o |
C |
34. |
In the diagram above, KLMN is a cyclic quadrilateral. /KL/ = /KN/, ∠NKM = 55o and ∠KML = 40o. Find ∠LKM A. 35o B. 40o C. 45o D. 50o E. 55o |
C |
35. |
In the diagram above, ∠SPQ = 79o. Find ∠SRQ A. 11o B. 391/2 C. 79o D. 90o E. 101o |
E |
36. |
Two angles (a + 31) and (b - 49o) are adjacent angles on a straight line. Which of the following is true A. a + b = 198o B. a + b = 180o C. a + b = 162o D. a + b = 100o E. a + b = 80o Detailed Solutiona + 31 + b - 49 = 180o(sum of angles on str line)a + b - 18 = 180o a + b = 180 + 18 a + b = 198o |
|
37. |
The trapezium PQRS parallel to SR,∠PQS = 34o and ∠SPQ = 2 ∠SRQ. Find the size of, SQR A. 58o B. 68o C. 78o D. 90o E. 112o Detailed Solutionconsidering SPQS = 34o (base ∠s of Isos. Δ) P = 180o - 68o = 112o R = 122/2 = 56o a = 34o (alt ∠s) SQR = 180o - (56 + 34) 180o - 90o = 90o |
|
38. |
In the diagram above, AB, CD and XY are straight lines intersecting at W. Find ∠CWX A. 20o B. 80o C. 100o D. 120o E. 140o Detailed Solutiona + b + c = 180o (sum of ∠s on a str line) 40o + 60o + c = 180o C = 180o - 100o C = 80o |
|
39. |
If sin\(\theta\) cos\(\theta\), for 0o \(\leq\) θ \(\leq\) 360o, find the value of \(\theta\) A. 45o, 225o B. 135o, 315o C. 45o, 315o D. 135o, 225o E. 45o, 135o |
A |
40. |
If tan x = \(2\frac{2}{5}\), find the value of sin x; 0 \(\leq\) x \(\leq\) 90o A. 5/13 B. 5/12 C. 144/169 D. 12/13 E. 13/12 Detailed SolutionTan x = 22/5 = 12/5sin x = 12/13 |
31. |
In the diagram above, /PQ/ = /PS/ and /QR/ = /SR/. Which of the following is/are true? i. the line PR bisects ∠QRS ii. The line PR is the perpendicular bisector of the line segment QS iii. Every point on PR is equidistant from SP and QP A. I only B. III only C. I and II only D. I and III only E. I, II and III |
E |
32. |
In the diagram, ∠PMN = ∠PRQ and ∠PNM = ∠PQR. If /Pm/ = 3cm, /MQ/ = 7cm and /PN/ = 5cm, find /NR/ A. 1cm B. 3cm C. 31/2 D. 5cm E. 6cm |
A |
33. |
In the diagram above, PQ is a tangent to the circle MTN at T. What is the size of ∠MTN? A. 52o B. 54o C. 66o D. 72o E. 128o |
C |
34. |
In the diagram above, KLMN is a cyclic quadrilateral. /KL/ = /KN/, ∠NKM = 55o and ∠KML = 40o. Find ∠LKM A. 35o B. 40o C. 45o D. 50o E. 55o |
C |
35. |
In the diagram above, ∠SPQ = 79o. Find ∠SRQ A. 11o B. 391/2 C. 79o D. 90o E. 101o |
E |
36. |
Two angles (a + 31) and (b - 49o) are adjacent angles on a straight line. Which of the following is true A. a + b = 198o B. a + b = 180o C. a + b = 162o D. a + b = 100o E. a + b = 80o Detailed Solutiona + 31 + b - 49 = 180o(sum of angles on str line)a + b - 18 = 180o a + b = 180 + 18 a + b = 198o |
|
37. |
The trapezium PQRS parallel to SR,∠PQS = 34o and ∠SPQ = 2 ∠SRQ. Find the size of, SQR A. 58o B. 68o C. 78o D. 90o E. 112o Detailed Solutionconsidering SPQS = 34o (base ∠s of Isos. Δ) P = 180o - 68o = 112o R = 122/2 = 56o a = 34o (alt ∠s) SQR = 180o - (56 + 34) 180o - 90o = 90o |
|
38. |
In the diagram above, AB, CD and XY are straight lines intersecting at W. Find ∠CWX A. 20o B. 80o C. 100o D. 120o E. 140o Detailed Solutiona + b + c = 180o (sum of ∠s on a str line) 40o + 60o + c = 180o C = 180o - 100o C = 80o |
|
39. |
If sin\(\theta\) cos\(\theta\), for 0o \(\leq\) θ \(\leq\) 360o, find the value of \(\theta\) A. 45o, 225o B. 135o, 315o C. 45o, 315o D. 135o, 225o E. 45o, 135o |
A |
40. |
If tan x = \(2\frac{2}{5}\), find the value of sin x; 0 \(\leq\) x \(\leq\) 90o A. 5/13 B. 5/12 C. 144/169 D. 12/13 E. 13/12 Detailed SolutionTan x = 22/5 = 12/5sin x = 12/13 |