Year : 
2017
Title : 
Mathematics (Core)
Exam : 
JAMB Exam

Paper 1 | Objectives

31 - 40 of 45 Questions

# Question Ans
31.

In how many ways can the word MACICITA be arranged?

A. \(\frac{8!}{2!}\)

B. \(\frac{8!}{3! 2!}\)

C. \(\frac{8!}{2! 2! 2!}\)

D. 8!

Detailed Solution

There is an explanation video available below.
32.

Y is inversely proportional to x and y is 6 when x = 7. Find the constant of the variation

A. 47

B. 42

C. 54

D. 46

Detailed Solution

Y ∝ \(\frac{1}{2}\)

Y = 6, X = 7

Y = \(\frac{k}{x}\) where k is constant

6 = \(\frac{k}{7}\)

k = 42
There is an explanation video available below.
33.

Find the equation of the locus of a point p (x, y) such that pv = pw, where v= (1, 1) and w = (3, 5)

A. 2x + 2y = 9

B. 2x + 3y = 8

C. 2x + y = 9

D. x + 2y = 8

Detailed Solution

There is an explanation video available below.
34.

Find ∫(x2 + 3x − 5)dx

A. \(\frac{x_3}{3}\) - \(\frac{3x_2}{2}\) - 5x + k

B. \(\frac{x_3}{3}\) - \(\frac{3x_2}{2}\) + 5x + k

C. \(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) - 5x + k

D. \(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) + 5x + k

Detailed Solution

There is an explanation video available below.
35.

In the diagram above MN is a chord of a circle KMN centre O and radius 10cm. If < MON = 140°, find, to the nearest cm, the length of the chord MN.

A. 10cm

B. 19cm

C. 17cm

D. 12cm

Detailed Solution

Find the diagram
Sin 70°

x = 10 Sin 70°

= 9.3969

Hence, length of chord MN = 2x

= 2 × 9.3969

= 18.79

= 19cm (nearest cm)
There is an explanation video available below.
36.

Factorize completely X2+2XY+Y2+3X+3Y-18

A. (x + y + 6)(x + y -3)

B. (x - y - 6)(x - y + 3)

C. (x - y + 6)(x - y - 3)

D. (x + y - 6)(x + y + 3)

Detailed Solution

\(x^{2} + 2xy + y^{2} + 3x + 3y - 18\)

\(x^{2} + 2xy + 3x + y^{2} + 3y -18\)

\(x^{2} + 2xy - 3x + 6x + y^{2} -3y + 6y -18\)

\(x^{2} + 2xy -3x + y^{2} -3y + 6x + 6y -18\)

\(x^{2} + xy -3x + xy + y^{2} - 3y + 6x + 6y -18\)

x(x + y - 3) + y(x + y - 3) + 6(x + y - 3)

= (x + y - 3)(x + y + 6)

= (x + y + 6)(x + y -3)
There is an explanation video available below.
37.

Make S the subject of the relation
p = s + \(\frac{sm^2}{nr}\)

A. s = \(\frac{nrp}{nr + m^2}\)

B. s = nr + \(\frac{m^2}{mrp}\)

C. s = \(\frac{nrp}{mr}\) + m2

D. s = \(\frac{nrp}{nr}\) + m2

Detailed Solution

p = s + \(\frac{sm^2}{nr}\)

p = s + ( 1 + \(\frac{m^2}{nr}\))

p = s (1 + \(\frac{nr + m^2}{nr}\))

nr × p = s (nr + m2)

s = \(\frac{nrp}{nr + m^2}\)
There is an explanation video available below.
38.

The operation * on the set R of real number is defined by x * y = 3x + 2y − 1, find 3* − 1

A. 9

B. - 9

C. 6

D. - 6

Detailed Solution

There is an explanation video available below.
39.

Find the gradient of the line joining the points (3, 2) and (1, 4)

A. 3/2

B. 2/1

C. -1

D. 3/2

Detailed Solution

There is an explanation video available below.
40.

Simplify (3√64a3)\(^{−1}\)

A. 4a

B. \(\frac{1}{8a}\)

C. 8a

D. \(\frac{1}{4a}\)

Detailed Solution

There is an explanation video available below.
31.

In how many ways can the word MACICITA be arranged?

A. \(\frac{8!}{2!}\)

B. \(\frac{8!}{3! 2!}\)

C. \(\frac{8!}{2! 2! 2!}\)

D. 8!

Detailed Solution

There is an explanation video available below.
32.

Y is inversely proportional to x and y is 6 when x = 7. Find the constant of the variation

A. 47

B. 42

C. 54

D. 46

Detailed Solution

Y ∝ \(\frac{1}{2}\)

Y = 6, X = 7

Y = \(\frac{k}{x}\) where k is constant

6 = \(\frac{k}{7}\)

k = 42
There is an explanation video available below.
33.

Find the equation of the locus of a point p (x, y) such that pv = pw, where v= (1, 1) and w = (3, 5)

A. 2x + 2y = 9

B. 2x + 3y = 8

C. 2x + y = 9

D. x + 2y = 8

Detailed Solution

There is an explanation video available below.
34.

Find ∫(x2 + 3x − 5)dx

A. \(\frac{x_3}{3}\) - \(\frac{3x_2}{2}\) - 5x + k

B. \(\frac{x_3}{3}\) - \(\frac{3x_2}{2}\) + 5x + k

C. \(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) - 5x + k

D. \(\frac{x_3}{3}\) + \(\frac{3x_2}{2}\) + 5x + k

Detailed Solution

There is an explanation video available below.
35.

In the diagram above MN is a chord of a circle KMN centre O and radius 10cm. If < MON = 140°, find, to the nearest cm, the length of the chord MN.

A. 10cm

B. 19cm

C. 17cm

D. 12cm

Detailed Solution

Find the diagram
Sin 70°

x = 10 Sin 70°

= 9.3969

Hence, length of chord MN = 2x

= 2 × 9.3969

= 18.79

= 19cm (nearest cm)
There is an explanation video available below.
36.

Factorize completely X2+2XY+Y2+3X+3Y-18

A. (x + y + 6)(x + y -3)

B. (x - y - 6)(x - y + 3)

C. (x - y + 6)(x - y - 3)

D. (x + y - 6)(x + y + 3)

Detailed Solution

\(x^{2} + 2xy + y^{2} + 3x + 3y - 18\)

\(x^{2} + 2xy + 3x + y^{2} + 3y -18\)

\(x^{2} + 2xy - 3x + 6x + y^{2} -3y + 6y -18\)

\(x^{2} + 2xy -3x + y^{2} -3y + 6x + 6y -18\)

\(x^{2} + xy -3x + xy + y^{2} - 3y + 6x + 6y -18\)

x(x + y - 3) + y(x + y - 3) + 6(x + y - 3)

= (x + y - 3)(x + y + 6)

= (x + y + 6)(x + y -3)
There is an explanation video available below.
37.

Make S the subject of the relation
p = s + \(\frac{sm^2}{nr}\)

A. s = \(\frac{nrp}{nr + m^2}\)

B. s = nr + \(\frac{m^2}{mrp}\)

C. s = \(\frac{nrp}{mr}\) + m2

D. s = \(\frac{nrp}{nr}\) + m2

Detailed Solution

p = s + \(\frac{sm^2}{nr}\)

p = s + ( 1 + \(\frac{m^2}{nr}\))

p = s (1 + \(\frac{nr + m^2}{nr}\))

nr × p = s (nr + m2)

s = \(\frac{nrp}{nr + m^2}\)
There is an explanation video available below.
38.

The operation * on the set R of real number is defined by x * y = 3x + 2y − 1, find 3* − 1

A. 9

B. - 9

C. 6

D. - 6

Detailed Solution

There is an explanation video available below.
39.

Find the gradient of the line joining the points (3, 2) and (1, 4)

A. 3/2

B. 2/1

C. -1

D. 3/2

Detailed Solution

There is an explanation video available below.
40.

Simplify (3√64a3)\(^{−1}\)

A. 4a

B. \(\frac{1}{8a}\)

C. 8a

D. \(\frac{1}{4a}\)

Detailed Solution

There is an explanation video available below.