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Mathematics (Core)
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1989
Level: SHS
Time:
Type: Question Paper
Answers provided
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Paper has been added to Cart!
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1989
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
| # | Question | Ans |
|---|---|---|
| 1. |
If 3loga + 5loga - 6loga = log64, what is a? A. 4 B. 6 C. 8 D. 16 E. 32 Detailed Solutionloga3 + loga5 - loga6log( a3 * a5a6 ) = loga64a2 = 64 a = 8 |
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| 2. |
If the second and fourth term of a G.P are 8 and 32 respectively,what is the sum of the first four terms? A. 28 B. 40 C. 48 D. 60 E. 68 Detailed Solutionar = 8 .....(1)ar3 = 32 .....(2) r2 = 4 r = 2 ∴ a = 4 |
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| 3. |
 In the diagram above, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of ΔQPT A. 39cm2 B. 28cm2 C. 24cm2 D. 21cm2 E. 19cm2 Detailed SolutionArea of \(\Delta\)QST = 52cm\(^2\); height = 8cmb=base length; but A = 1/2 b x h =52=1/2 x b x 8cm = 104 =8b b=104/8 = 13cm; ST= 13cm; PS = 6cm TP = 13 - 6 = 7cm; area of \(\Delta\)QST = 1/2 b x h = 1/2 x 7 x 8/1 = 28cm\(^2\) |
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| 4. |
 In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR. A. 14o B. 28o C. 31o D. 45o E. 90o Detailed Solution< QSR = 90° (angle in a semi-circle)\(\therefore\) < SQR = 180° - (90° + 62°) = 28° |
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| 5. |
Evaluate, using logarithm tables \(\frac{5.34 \times 67.4}{2.7}\) A. 1.332 B. 13.32 C. 133.2 D. 1332 E. 13.320 Detailed Solution\(\therefore \frac{5.34 \times 67.4}{2.7} = 133.2\) |
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| 6. |
Factorize 35 - 2b - b2 A. (35-2b)(b-1) B. (7+b)(5-b) C. (3+7b)(5-b) D. (35-b)(3b+7) E. (7+b)(5+b) Detailed Solution35 - 2b - b 2;35 - 7b + 5b - b 2 7(5 - b) + 5(5 - b) (7 + b)(5 - b) |
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| 7. |
Evaluate \(\frac{0.009}{0.012}\), leaving your answer in standard form. A. 7.5 x 102 B. 7.5 x 101 C. 7.5 x 10-1 D. 7.5 x 10-2 E. 7.5 x 10-3 Detailed Solution\(\frac{0.009}{0.012}\)=\(\frac{0.009}{0.012}\) = \(\frac{9}{12}\) = 0.75 =\(7.5 \times 10^{-1}\) |
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| 8. |
 The graph above is that of a quadratic function y = 2x2 - x - 6 A. 1.5, 2 B. -1.5, 2 C. 1, -6 D. 1, 6 E. -1, 6 Detailed SolutionThe roots are; x = -1.5 and 2 |
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| 9. |
Factorize the following expression; 2x2 + x - 15 A. (2x+5)(x-3) B. (2x-5)(x+3) C. (2x-5)(x-3) D. (2x-3)(x+5) E. (2x+5)(x+3) Detailed Solution2x 2 + x - 15; 2x 2 + 6x - 5x - 15(2x 2 + 6x) - ( 5x + 15) 2x(x + 3) - 5(x + 3) (2x - 5)(x + 3) |
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| 10. |
The angle of elevation of X from Y is 30o. If XY = 40m, how high is X above the level of Y? A. 10m B. 20m C. 20√3m D. 40m E. 50m Detailed Solution
 = 20m |
Preview displays only 10 out of the 48 Questions
