Year : 
2003
Title : 
Mathematics (Core)
Exam : 
WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

1 - 10 of 46 Questions

# Question Ans
1.

Simplify \(\left(\frac{3}{4} - \frac{1}{3}\right)\times 4\frac{1}{3}\div 3\frac{1}{4}\)

A. \(\frac{5}{9}\)

B. \(\frac{5}{16}\)

C. \(\frac{8}{13}\)

D. \(\frac{16}{5}\)

Detailed Solution

\((\frac{3}{4} - \frac{1}{3}) \times 4\frac{1}{3} \div 3\frac{1}{4}\)
= \((\frac{9 - 4}{12}) \times \frac{13}{3} \div \frac{13}{4}\)
= \(\frac{5}{12} \times \frac{13}{3} \times \frac{4}{13}\)
= \(\frac{5}{9}\)
2.

The table below gives the distribution of marks obtained by a number of pupils in a class test.The mode of the distribution is

A. 3

B. 5

C. 8

D. 18

A
3.

The table below gives the distribution of marks obtained by a number of pupils in a class test.Find the median of the distribution

A. 1

B. 2

C. 3

D. 4

C
4.

The table below gives the distribution of marks obtained by a number of pupils in a class test.How many pupils scored at least 2 marks?

A. 12

B. 23

C. 37

D. 49

Detailed Solution

= 12 + 18 + 11 + 8
= 49 students
5.

Interprete the inequality represented on the number line

A. -4< X ≤ 5

B. -4 ≤ x< 5

C. -4

D. -4≤x≤5

A
6.

A student bought 3 notebooks and 1 pen for N35. After misplacing these items, she again bought 2 notebooks and 2 pens, all of the same type for
N30. What is the cost of a pen?

A. N5.00

B. N7.50

C. N10.00

D. N15.00

Detailed Solution

Represent notebook with x
Represent pen with y
∴ 3x+y=35 ---- (i)
2x+2y=30 ---- (ii)
Multiply eqn (i) by 2 and eqn (ii) by 1
6x+2y=70 ---- (iii)
2x+2y=30 ---- (iv)
Subtract eqn (iv) from eqn (iii)
4x = 40
X = 10
Substitute x = 10 in eqn (i)
3x+y=35
3(10)+y=35
Y = 5
∴ The cost of pen is N5.00
7.

Simplify \(\frac{4}{a-3}-\frac{1}{a+3}\)

A. \(\frac{3a+11}{(a-3)(a-2)}\)

B. \(\frac{3a+11}{(a+3)(a-2)}\)

C. \(\frac{3a+11}{(a+3)(a+2)}\)

D. \(\frac{3a+11}{(a-3)(a+2)}\)

Detailed Solution

\(\frac{4}{a-3}-\frac{1}{a+3}\\
= \frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\\
=\frac{3a+11}{(a-3)(a+2)}
\)
8.

Simplify \(\frac{4\sqrt{18}}{\sqrt{8}}\)

A. 2

B. 3

C. 6

D. 12

Detailed Solution

\(\frac{4\sqrt{18}}{\sqrt{8}}\\
= \frac{4\sqrt{9\times 2}}{\sqrt{4 \times 2}} = \frac{12\sqrt{2}}{2\sqrt{2}}=\frac{6\sqrt{2}}{\sqrt{2}}\\
Rationalising \frac{6\sqrt{2}}{\sqrt{2}}\\
=\frac{6\sqrt{2}}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 6\)
9.

In the diagram, PQ/RT /RS/ =/QS/, ∠QST= 70o and ∠PQW = 55o
Find the size of reflex ∠WQS

A. 235o

B. 290o

C. 305o

D. 325o

Detailed Solution

Reflex ∠WQS = 360o - (55o + 70o)
=360o - 125o = 235o
10.

Three men, Bedu, Bakre and Kofi shared' N500 in the ratio 3:2: x respectively. If Bedu’s share is N150, find the value of x.

A. 1

B. 4

C. 5

D. 6

Detailed Solution

\(5+x\rightarrow 500\\
3 \rightarrow 150\\
∴ 3 \times 500 = 150 \times (5+x)\\
1500 = 750 + 150x\\
x=\frac{750}{150}=5\)
1.

Simplify \(\left(\frac{3}{4} - \frac{1}{3}\right)\times 4\frac{1}{3}\div 3\frac{1}{4}\)

A. \(\frac{5}{9}\)

B. \(\frac{5}{16}\)

C. \(\frac{8}{13}\)

D. \(\frac{16}{5}\)

Detailed Solution

\((\frac{3}{4} - \frac{1}{3}) \times 4\frac{1}{3} \div 3\frac{1}{4}\)
= \((\frac{9 - 4}{12}) \times \frac{13}{3} \div \frac{13}{4}\)
= \(\frac{5}{12} \times \frac{13}{3} \times \frac{4}{13}\)
= \(\frac{5}{9}\)
2.

The table below gives the distribution of marks obtained by a number of pupils in a class test.The mode of the distribution is

A. 3

B. 5

C. 8

D. 18

A
3.

The table below gives the distribution of marks obtained by a number of pupils in a class test.Find the median of the distribution

A. 1

B. 2

C. 3

D. 4

C
4.

The table below gives the distribution of marks obtained by a number of pupils in a class test.How many pupils scored at least 2 marks?

A. 12

B. 23

C. 37

D. 49

Detailed Solution

= 12 + 18 + 11 + 8
= 49 students
5.

Interprete the inequality represented on the number line

A. -4< X ≤ 5

B. -4 ≤ x< 5

C. -4

D. -4≤x≤5

A
6.

A student bought 3 notebooks and 1 pen for N35. After misplacing these items, she again bought 2 notebooks and 2 pens, all of the same type for
N30. What is the cost of a pen?

A. N5.00

B. N7.50

C. N10.00

D. N15.00

Detailed Solution

Represent notebook with x
Represent pen with y
∴ 3x+y=35 ---- (i)
2x+2y=30 ---- (ii)
Multiply eqn (i) by 2 and eqn (ii) by 1
6x+2y=70 ---- (iii)
2x+2y=30 ---- (iv)
Subtract eqn (iv) from eqn (iii)
4x = 40
X = 10
Substitute x = 10 in eqn (i)
3x+y=35
3(10)+y=35
Y = 5
∴ The cost of pen is N5.00
7.

Simplify \(\frac{4}{a-3}-\frac{1}{a+3}\)

A. \(\frac{3a+11}{(a-3)(a-2)}\)

B. \(\frac{3a+11}{(a+3)(a-2)}\)

C. \(\frac{3a+11}{(a+3)(a+2)}\)

D. \(\frac{3a+11}{(a-3)(a+2)}\)

Detailed Solution

\(\frac{4}{a-3}-\frac{1}{a+3}\\
= \frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\\
=\frac{3a+11}{(a-3)(a+2)}
\)
8.

Simplify \(\frac{4\sqrt{18}}{\sqrt{8}}\)

A. 2

B. 3

C. 6

D. 12

Detailed Solution

\(\frac{4\sqrt{18}}{\sqrt{8}}\\
= \frac{4\sqrt{9\times 2}}{\sqrt{4 \times 2}} = \frac{12\sqrt{2}}{2\sqrt{2}}=\frac{6\sqrt{2}}{\sqrt{2}}\\
Rationalising \frac{6\sqrt{2}}{\sqrt{2}}\\
=\frac{6\sqrt{2}}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 6\)
9.

In the diagram, PQ/RT /RS/ =/QS/, ∠QST= 70o and ∠PQW = 55o
Find the size of reflex ∠WQS

A. 235o

B. 290o

C. 305o

D. 325o

Detailed Solution

Reflex ∠WQS = 360o - (55o + 70o)
=360o - 125o = 235o
10.

Three men, Bedu, Bakre and Kofi shared' N500 in the ratio 3:2: x respectively. If Bedu’s share is N150, find the value of x.

A. 1

B. 4

C. 5

D. 6

Detailed Solution

\(5+x\rightarrow 500\\
3 \rightarrow 150\\
∴ 3 \times 500 = 150 \times (5+x)\\
1500 = 750 + 150x\\
x=\frac{750}{150}=5\)