Year : 
1997
Title : 
Chemistry
Exam : 
WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

1 - 10 of 48 Questions

# Question Ans
1.

The phenomenon observed when dust particles collide randomly in a beam of sunlight is known as

A. Tyndal effect

B. diffusion

C. osmosis

D. brownian movement

E. dialysis

A

2.

The mass number of an element is the sum of its

A. electrons, neutrons and protons

B. electrons and protons

C. protons and neutrons

D. orbital electrons

E. valence electrons

C

3.

How many unpaired electrons are there in an atom of an element with the following electronic configuration? 1s22s22p6

A. o

B. 1

C. 2

D. 6

E. 8

A

4.

Radon is used as a tracer in medical research because it

A. is monatomic

B. is radioactive

C. is a noble gas

D. has a complete valence shell

E. has a low boiling point

B

5.

What is the most probable group of an element which is a soft, silvery white solid and reacts violently with water?

A. Group 0

B. Group 1

C. Group 4

D. Group 6

E. Group 7

B

6.

In linear molecules, the bond angle is

A. 90o

B. 140o

C. 109o

D. 120o

E. 180o

E

7.

A sodium atom and a sodium ion have the same

A. number of neutrons

B. number of electrons

C. electric charge

D. electronic structure

E. chemical properties

A

8.

If the atomic number of an element X is 11 and that of nitrogen is 7, the most likely formula of the nitride of X is

A. X3N

B. XN3

C. X3N2

D. N2X

E. NX2

A

9.

An increase in the pressure of a gas results in a decrease in its

A. mass

B. vapour density

C. volume

D. temperature

E. concentration

C

10.

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]

A. 5 seconds

B. 20 seconds

C. 40 seconds

D. 60 seconds

E. 80 seconds

Detailed Solution

Applying the Graham's law defination; i.e,
\(\frac{R(SO_2)}{R(CH_4)} = \sqrt{\frac{M(CH_4)}{M(SO_2)}} = \frac{t(CH_4)}{t(SO_2)}\)
Where t(SO\(_2\)) = ?, M(SO\(_2\)) = 64
t(Ch\(_4\)) = 20 sec, M(Ch\(_4\)) = 16
therefore, \(\frac{t(SO_2)}{20}\) = \(\sqrt{\frac{64}{16}}\)
\(\frac{t(SO_2)}{20}\) = \(\frac{8}{4}\)
t(SO\(_2\)) = 8 x \(\frac{20}{4}\)
= 40 sec.
1.

The phenomenon observed when dust particles collide randomly in a beam of sunlight is known as

A. Tyndal effect

B. diffusion

C. osmosis

D. brownian movement

E. dialysis

A

2.

The mass number of an element is the sum of its

A. electrons, neutrons and protons

B. electrons and protons

C. protons and neutrons

D. orbital electrons

E. valence electrons

C

3.

How many unpaired electrons are there in an atom of an element with the following electronic configuration? 1s22s22p6

A. o

B. 1

C. 2

D. 6

E. 8

A

4.

Radon is used as a tracer in medical research because it

A. is monatomic

B. is radioactive

C. is a noble gas

D. has a complete valence shell

E. has a low boiling point

B

5.

What is the most probable group of an element which is a soft, silvery white solid and reacts violently with water?

A. Group 0

B. Group 1

C. Group 4

D. Group 6

E. Group 7

B

6.

In linear molecules, the bond angle is

A. 90o

B. 140o

C. 109o

D. 120o

E. 180o

E

7.

A sodium atom and a sodium ion have the same

A. number of neutrons

B. number of electrons

C. electric charge

D. electronic structure

E. chemical properties

A

8.

If the atomic number of an element X is 11 and that of nitrogen is 7, the most likely formula of the nitride of X is

A. X3N

B. XN3

C. X3N2

D. N2X

E. NX2

A

9.

An increase in the pressure of a gas results in a decrease in its

A. mass

B. vapour density

C. volume

D. temperature

E. concentration

C

10.

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]

A. 5 seconds

B. 20 seconds

C. 40 seconds

D. 60 seconds

E. 80 seconds

Detailed Solution

Applying the Graham's law defination; i.e,
\(\frac{R(SO_2)}{R(CH_4)} = \sqrt{\frac{M(CH_4)}{M(SO_2)}} = \frac{t(CH_4)}{t(SO_2)}\)
Where t(SO\(_2\)) = ?, M(SO\(_2\)) = 64
t(Ch\(_4\)) = 20 sec, M(Ch\(_4\)) = 16
therefore, \(\frac{t(SO_2)}{20}\) = \(\sqrt{\frac{64}{16}}\)
\(\frac{t(SO_2)}{20}\) = \(\frac{8}{4}\)
t(SO\(_2\)) = 8 x \(\frac{20}{4}\)
= 40 sec.