Year : 
1980
Title : 
Mathematics (Core)
Exam : 
JAMB Exam

Paper 1 | Objectives

1 - 10 of 49 Questions

# Question Ans
1.

Find, correct to three significant figures, the value of \(\sqrt{41830}\).

A. 205

B. 647

C. 2050

D. 6470

E. 64.7

Detailed Solution

\(\sqrt{41830} = 204.5238\)
\(\approxeq 205\) (to three significant figures)
2.

Write down the number 0.0052048 correct to three significant figures

A. 0.005

B. 0.0052

C. 0.00520

D. 5.2048

E. 5204

Detailed Solution

0.0052048 = 0.00520
3.

Evaluate \((2^{0} + 4^{-\frac{1}{2}})^{2}\)

A. \(\frac{1}{4}\)

B. \(\frac{5}{4}\)

C. \(\frac{9}{4}\)

D. 4

E. 9

Detailed Solution

\((2^{0} + 4^{-\frac{1}{2}})^{2}\)
= \((1 + (\frac{1}{4})^{\frac{1}{2}})^{2}\)
= \((1 + \frac{1}{2})^{2}\)
= \((\frac{3}{2})^{2} = \frac{9}{4}\)
4.

Which of the following is NOT a factor of 12\(^{4}\) - 5\(^{4}\)?

A. 7

B. 13

C. 17

D. 49

E. 169

Detailed Solution

124 - 54 = (122)2 - (52)2

= (122 + 52) x (122 - 52)

(144 + 25)(144 - 25)

= (169)(119)

Factors of above 169, 17, 13, 7
5.

Rationalize the denominator of the given expression \(\frac{\sqrt{1 + a} - \sqrt{a}}{1 + a + \sqrt{a}}\)

A. 1 + 2a - 2\(\sqrt{a(1 + a)}\)

B. \(\sqrt{1(1 + a)}\)

C. 2a - 2\(\sqrt{a(1 + a)}\)

D. 1 + 2a - 2\(\sqrt{a + b}\)

Detailed Solution

\(\frac{\sqrt{1 + a} - \sqrt{a}}{1 + a + \sqrt{a}}\) = \(\frac{\sqrt{1 + a} - \sqrt{a}}{\sqrt{1 + a} + \sqrt{a}}\) x \(\frac{\sqrt{1 + a} - \sqrt{a}}{\sqrt{1 + a} - \sqrt{a}}\)

= \(\frac{\sqrt{1 + a + a}}{1 + a - a}\)

= 2a + a(1 + a)

= 1 + 2a - 2\(\sqrt{a(1 + a)}\)
6.

When a dealer sells a bicycle for N81 he makes a profit of 80%. What did he pay for the bicycle?

A. N73

B. N74.52

C. N75

D. N87.48

E. N75.52

Detailed Solution

Profit = 8%
\(\therefore S.P = N81 = (100 + 8)% = 108%\)
\(108% = N81\)
\(100% = \frac{81}{108} \times 100\)
= \(\frac{8100}{108} = N75\)
7.

The median of the set of numbers 4, 9, 4, 13, 7, 14, 10, 17 is

A. 13

B. 7

C. \(\frac{19}{2}\)

D. \(\frac{39}{4}\)

E. 10

Detailed Solution

Rearranging in increasing order 4, 4, 7, 9, 10, 13, 14, 17, the

median = \(\frac{(9 + 10)}{2}\)

= \(\frac{19}{2}\)
8.

List all integer values of x satisfying the inequality -1 < 2x - 5 \(\leq\) 5

A. <2, 3, 4, 5

B. 3, 4, 5

C. 2, 3, 4

D. 3, 4

Detailed Solution

\(-1 < 2x - 5 \leq 5\)
\(\implies -1 + 5 < 2x - 5 + 5 \leq 5 + 5\)
\(4 < 2x \leq 10\)
\(\implies 2 < x \leq 5 \)
= 3, 4, 5.
9.

Find the roots of the equation 10x2 - 13x - 3 = 0

A. x = \(\frac{3}{5}\) or -\(\frac{1}{2}\)

B. x = \(\frac{3}{10}\) or -1

C. x = \(\frac{3}{10}\) or 1

D. x = \(\frac{1}{5}\) or \(\frac{-3}{2}\)

E. x = -\(\frac{1}{5}\) or \(\frac{3}{2}\)

Detailed Solution

10x2 - 13x - 3 = 0 = 10x2 - 15x + 2x - 3 = 0

5x(2x - 3) + 2x - 3 = 0

= (5x + 1)(2x - 3) = 0

5x + 1 = 0 or 2x - 3 = 0

x = -\(\frac{1}{5}\) or \(\frac{3}{2}\)
10.

A solid cylinder of radius 3cm has a total surface area of 36\(\pi\)cm2. Find its height

A. 2cm

B. 3cm

C. 4cm

D. 5cm

E. 6cm

Detailed Solution

Area 2\(\pi\)r2 + 2 \(\pi\)r(r + h)

= 2\(\pi\)r(r + h)

36\(\pi\) = 6\(\pi\)(r + h)

36\(\pi\) = 6\(\pi\)(3 + h)

36\(\pi\) = 18\(\pi\) + 6\(\pi\)h

36\(\pi\) - 18\(\pi\) = 6\(\pi\)h

Divide both side by 6\(\pi\)

h = 3cm
1.

Find, correct to three significant figures, the value of \(\sqrt{41830}\).

A. 205

B. 647

C. 2050

D. 6470

E. 64.7

Detailed Solution

\(\sqrt{41830} = 204.5238\)
\(\approxeq 205\) (to three significant figures)
2.

Write down the number 0.0052048 correct to three significant figures

A. 0.005

B. 0.0052

C. 0.00520

D. 5.2048

E. 5204

Detailed Solution

0.0052048 = 0.00520
3.

Evaluate \((2^{0} + 4^{-\frac{1}{2}})^{2}\)

A. \(\frac{1}{4}\)

B. \(\frac{5}{4}\)

C. \(\frac{9}{4}\)

D. 4

E. 9

Detailed Solution

\((2^{0} + 4^{-\frac{1}{2}})^{2}\)
= \((1 + (\frac{1}{4})^{\frac{1}{2}})^{2}\)
= \((1 + \frac{1}{2})^{2}\)
= \((\frac{3}{2})^{2} = \frac{9}{4}\)
4.

Which of the following is NOT a factor of 12\(^{4}\) - 5\(^{4}\)?

A. 7

B. 13

C. 17

D. 49

E. 169

Detailed Solution

124 - 54 = (122)2 - (52)2

= (122 + 52) x (122 - 52)

(144 + 25)(144 - 25)

= (169)(119)

Factors of above 169, 17, 13, 7
5.

Rationalize the denominator of the given expression \(\frac{\sqrt{1 + a} - \sqrt{a}}{1 + a + \sqrt{a}}\)

A. 1 + 2a - 2\(\sqrt{a(1 + a)}\)

B. \(\sqrt{1(1 + a)}\)

C. 2a - 2\(\sqrt{a(1 + a)}\)

D. 1 + 2a - 2\(\sqrt{a + b}\)

Detailed Solution

\(\frac{\sqrt{1 + a} - \sqrt{a}}{1 + a + \sqrt{a}}\) = \(\frac{\sqrt{1 + a} - \sqrt{a}}{\sqrt{1 + a} + \sqrt{a}}\) x \(\frac{\sqrt{1 + a} - \sqrt{a}}{\sqrt{1 + a} - \sqrt{a}}\)

= \(\frac{\sqrt{1 + a + a}}{1 + a - a}\)

= 2a + a(1 + a)

= 1 + 2a - 2\(\sqrt{a(1 + a)}\)
6.

When a dealer sells a bicycle for N81 he makes a profit of 80%. What did he pay for the bicycle?

A. N73

B. N74.52

C. N75

D. N87.48

E. N75.52

Detailed Solution

Profit = 8%
\(\therefore S.P = N81 = (100 + 8)% = 108%\)
\(108% = N81\)
\(100% = \frac{81}{108} \times 100\)
= \(\frac{8100}{108} = N75\)
7.

The median of the set of numbers 4, 9, 4, 13, 7, 14, 10, 17 is

A. 13

B. 7

C. \(\frac{19}{2}\)

D. \(\frac{39}{4}\)

E. 10

Detailed Solution

Rearranging in increasing order 4, 4, 7, 9, 10, 13, 14, 17, the

median = \(\frac{(9 + 10)}{2}\)

= \(\frac{19}{2}\)
8.

List all integer values of x satisfying the inequality -1 < 2x - 5 \(\leq\) 5

A. <2, 3, 4, 5

B. 3, 4, 5

C. 2, 3, 4

D. 3, 4

Detailed Solution

\(-1 < 2x - 5 \leq 5\)
\(\implies -1 + 5 < 2x - 5 + 5 \leq 5 + 5\)
\(4 < 2x \leq 10\)
\(\implies 2 < x \leq 5 \)
= 3, 4, 5.
9.

Find the roots of the equation 10x2 - 13x - 3 = 0

A. x = \(\frac{3}{5}\) or -\(\frac{1}{2}\)

B. x = \(\frac{3}{10}\) or -1

C. x = \(\frac{3}{10}\) or 1

D. x = \(\frac{1}{5}\) or \(\frac{-3}{2}\)

E. x = -\(\frac{1}{5}\) or \(\frac{3}{2}\)

Detailed Solution

10x2 - 13x - 3 = 0 = 10x2 - 15x + 2x - 3 = 0

5x(2x - 3) + 2x - 3 = 0

= (5x + 1)(2x - 3) = 0

5x + 1 = 0 or 2x - 3 = 0

x = -\(\frac{1}{5}\) or \(\frac{3}{2}\)
10.

A solid cylinder of radius 3cm has a total surface area of 36\(\pi\)cm2. Find its height

A. 2cm

B. 3cm

C. 4cm

D. 5cm

E. 6cm

Detailed Solution

Area 2\(\pi\)r2 + 2 \(\pi\)r(r + h)

= 2\(\pi\)r(r + h)

36\(\pi\) = 6\(\pi\)(r + h)

36\(\pi\) = 6\(\pi\)(3 + h)

36\(\pi\) = 18\(\pi\) + 6\(\pi\)h

36\(\pi\) - 18\(\pi\) = 6\(\pi\)h

Divide both side by 6\(\pi\)

h = 3cm